SciPy — Optimization
Scalar optimization
from scipy.optimize import minimize_scalar
def f(x):
return (x - 3)**2 + 2
result = minimize_scalar(f)
print(f"Minimum at x = {result.x:.2f}")
print(f"Minimum value = {result.fun:.2f}")
Bounded optimization
result = minimize_scalar(f, bounds=(0, 5), method='bounded')
print(f"Minimum in [0,5]: x = {result.x:.2f}")
Multivariate optimization
from scipy.optimize import minimize
def objective(x):
return (x[0] - 1)**2 + (x[1] - 2)**2
x0 = [0, 0]
result = minimize(objective, x0, method='L-BFGS-B')
print(f"Optimal: x = {result.x}")
Constrained optimization
from scipy.optimize import minimize
def objective(x):
return x[0]**2 + x[1]**2
constraints = [
{'type': 'eq', 'fun': lambda x: x[0] + x[1] - 1}
]
result = minimize(objective, [0, 0], constraints=constraints)
print(f"Optimal: x = {result.x}")
Curve fitting
from scipy.optimize import curve_fit
import numpy as np
def model(x, a, b):
return a * np.exp(b * x)
x = np.array([0, 1, 2, 3, 4])
y = np.array([1, 2.7, 7.4, 20.1, 54.6])
popt, pcov = curve_fit(model, x, y)
print(f"a = {popt[0]:.2f}, b = {popt[1]:.2f}")
Root finding
from scipy.optimize import fsolve
def f(x):
return x**2 - 4
root = fsolve(f, 1)
print(f"Root: {root[0]:.2f}")
Mini Practice
- Find minimum of a function
- Optimize with constraints
- Fit a curve to data
- Find roots of an equation
Up Next
Continue with Interpolation - Estimating values.
Related Topics
Frequently Asked Questions about Optimization
What is Optimization in SciPy?
Optimization is a fundamental concept in SciPy. This lesson explains it step by step with clear examples, making it easy for beginners to understand.
How do I learn Optimization?
Start by reading the explanation above, then try the code examples. Practice by modifying the examples and experimenting with different values. Hands-on practice is the best way to learn Optimization.
Why is Optimization important in SciPy?
Optimization is essential for SciPy development. Understanding this concept will help you write better code and solve real-world problems more effectively.